Talk:Fermat point

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[edit] Incomplete Proof?

As I was reading through the proof, I found it to be (to the best of my knowledge) incomplete. Here is why: "Because AR=AB, AC=AQ, by construction, and because angle RAC = angle BAQ, therefore triangle RAC and BAQ are congruent." Is it assumed that RC = BQ? If not, I do not see any proof that <RAC = <BAQ.

Now, I am no math wiz. If I am missing something here, please forgive my ignorance.

Angle RAC = angle RAB + angle BAC and angle BAQ = angle BAC + angle CAQ. Both angle RAB and angle CAQ are 60 degrees, because the triangles RAB and CAQ are equilateral, and hence <RAC = <BAQ. -- Jitse Niesen (talk) 02:17, 19 March 2006 (UTC)

Ah, yes, that makes sense. Thanks for the quick response! I have updated the main page accordingly.
Wolever 03:37, 19 March 2006 (UTC)