Douglas, Nebraska

From Wikipedia, the free encyclopedia

Douglas is a village in Otoe County, Nebraska, United States. The population was 231 at the 2000 census.

[edit] Geography

Douglas is located at 40°35′35″N, 96°23′14″W (40.592966, -96.387099)^GR1.

According to the United States Census Bureau, the village has a total area of 0.6 km² (0.2 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 231 people, 91 households, and 58 families residing in the village. The population density was 405.4/km² (1,038.7/mi²). There were 96 housing units at an average density of 168.5/km² (431.7/mi²). The racial makeup of the village was 97.84% White, 1.30% African American, and 0.87% from two or more races.

There were 91 households out of which 29.7% had children under the age of 18 living with them, 56.0% were married couples living together, 4.4% had a female householder with no husband present, and 35.2% were non-families. 28.6% of all households were made up of individuals and 12.1% had someone living alone who was 65 years of age or older. The average household size was 2.54 and the average family size was 3.24.

In the village the population was spread out with 26.8% under the age of 18, 7.8% from 18 to 24, 32.0% from 25 to 44, 23.4% from 45 to 64, and 10.0% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 97.4 males. For every 100 females age 18 and over, there were 108.6 males.

The median income for a household in the village was $33,594, and the median income for a family was $38,889. Males had a median income of $28,125 versus $20,938 for females. The per capita income for the village was $15,174. About 6.9% of families and 14.1% of the population were below the poverty line, including 30.2% of those under the age of eighteen and 18.2% of those sixty five or over.