Talk:Dividing a circle into areas

Just found this (odd) page.

$f(n)=f(n-1)+\sum^{n-1}_{i=1}\left(2-n+ni-i^2\right)$

$=f(n-1)-n^2+3n-2+\sum^{n-1}_{i=1}\left(ni-i^2\right)$

Well, I guess this is like

f(n) - f(n-1) = C(n)

with c(n) cubic, so the answer is a quartic?

Anyone want to go in and sort this out?

Charles Matthews 17:38, 9 Feb 2004 (UTC)