Dane (town), Wisconsin
From Wikipedia, the free encyclopedia
Dane is a town in Dane County, Wisconsin, United States. The population was 968 at the 2000 census.
[edit] Geography
According to the United States Census Bureau, the town has a total area of 90.9 km² (35.1 mi²). 90.9 km² (35.1 mi²) of it is land and 0.03% is water.
[edit] Demographics
As of the census2 of 2000, there were 968 people, 335 households, and 271 families residing in the town. The population density was 10.6/km² (27.6/mi²). There were 339 housing units at an average density of 3.7/km² (9.7/mi²). The racial makeup of the town was 98.76% White, 0.21% Native American, 0.52% Asian, 0.21% from other races, and 0.31% from two or more races. 0.52% of the population were Hispanic or Latino of any race.
There were 335 households out of which 39.1% had children under the age of 18 living with them, 74.3% were married couples living together, 2.1% had a female householder with no husband present, and 19.1% were non-families. 12.2% of all households were made up of individuals and 6.0% had someone living alone who was 65 years of age or older. The average household size was 2.89 and the average family size was 3.20.
In the town the population was spread out with 29.1% under the age of 18, 6.7% from 18 to 24, 29.9% from 25 to 44, 23.8% from 45 to 64, and 10.5% who were 65 years of age or older. The median age was 37 years. For every 100 females there were 106.0 males. For every 100 females age 18 and over, there were 105.4 males.
The median income for a household in the town was $61,250, and the median income for a family was $64,423. Males had a median income of $36,016 versus $32,679 for females. The per capita income for the town was $25,562. About 2.9% of families and 3.2% of the population were below the poverty line, including 3.2% of those under age 18 and 3.1% of those age 65 or over.
