Culdesac, Idaho

From Wikipedia, the free encyclopedia

Culdesac is a city in Nez Perce County, Idaho, United States. The population was 378 at the 2000 census. It is a part of the Lewiston metropolitan statistical area.

[edit] Geography

Culdesac is located at 46°22′30″N, 116°40′13″W (46.374883, -116.670333)^GR1.

According to the United States Census Bureau, the city has a total area of 0.6 km² (0.2 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 378 people, 152 households, and 107 families residing in the city. The population density was 608.1/km² (1,601.4/mi²). There were 171 housing units at an average density of 275.1/km² (724.5/mi²). The racial makeup of the city was 94.44% White, 0.53% African American, 2.65% Native American, 0.26% Pacific Islander, 0.26% from other races, and 1.85% from two or more races. Hispanic or Latino of any race were 1.59% of the population.

There were 152 households out of which 34.2% had children under the age of 18 living with them, 53.3% were married couples living together, 9.9% had a female householder with no husband present, and 29.6% were non-families. 25.7% of all households were made up of individuals and 10.5% had someone living alone who was 65 years of age or older. The average household size was 2.49 and the average family size was 2.98.

In the city the population was spread out with 28.3% under the age of 18, 5.8% from 18 to 24, 26.7% from 25 to 44, 26.2% from 45 to 64, and 13.0% who were 65 years of age or older. The median age was 37 years. For every 100 females there were 100.0 males. For every 100 females age 18 and over, there were 90.8 males.

The median income for a household in the city was $25,750, and the median income for a family was $31,364. Males had a median income of $27,500 versus $22,083 for females. The per capita income for the city was $11,888. About 14.4% of families and 16.4% of the population were below the poverty line, including 13.0% of those under age 18 and none of those age 65 or over.