Crawfordsville, Iowa

From Wikipedia, the free encyclopedia

Crawfordsville is a city in Washington County, Iowa, United States. It part of the Iowa City, Iowa Metropolitan Statistical Area. The population was 295 at the 2000 census.

[edit] Geography

Crawfordsville is located at 41°12′55″N, 91°32′16″W (41.215393, -91.537844)^GR1.

According to the United States Census Bureau, the city has a total area of 1.0 km² (0.4 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 295 people, 117 households, and 78 families residing in the city. The population density was 307.8/km² (803.0/mi²). There were 122 housing units at an average density of 127.3/km² (332.1/mi²). The racial makeup of the city was 99.66% White and 0.34% Native American. Hispanic or Latino of any race were 1.02% of the population.

There were 117 households out of which 37.6% had children under the age of 18 living with them, 54.7% were married couples living together, 8.5% had a female householder with no husband present, and 33.3% were non-families. 29.1% of all households were made up of individuals and 11.1% had someone living alone who was 65 years of age or older. The average household size was 2.52 and the average family size was 3.13.

In the city the population was spread out with 29.8% under the age of 18, 6.4% from 18 to 24, 30.5% from 25 to 44, 16.3% from 45 to 64, and 16.9% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 102.1 males. For every 100 females age 18 and over, there were 99.0 males.

The median income for a household in the city was $39,063, and the median income for a family was $38,571. Males had a median income of $28,036 versus $22,813 for females. The per capita income for the city was $17,238. None of the families and 2.0% of the population were living below the poverty line, including no under eighteens and 6.1% of those over 64.