Clinton, Nebraska

From Wikipedia, the free encyclopedia

Clinton is a village in Sheridan County, Nebraska, United States. The population was 30 at the 2000 census.

[edit] Geography

Clinton is located at 42°45′34″N, 102°20′55″W (42.759365, -102.348670)^GR1.

According to the United States Census Bureau, the village has a total area of 0.2 km² (0.1 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 30 people, 16 households, and 11 families residing in the village. The population density was 128.7/km² (319.7/mi²). There were 17 housing units at an average density of 72.9/km² (181.1/mi²). The racial makeup of the village was 96.67% White, and 3.33% from two or more races.

There were 16 households out of which 6.3% had children under the age of 18 living with them, 56.3% were married couples living together, 12.5% had a female householder with no husband present, and 31.3% were non-families. 31.3% of all households were made up of individuals and 12.5% had someone living alone who was 65 years of age or older. The average household size was 1.88 and the average family size was 2.27.

In the village the population was spread out with 6.7% under the age of 18, 3.3% from 18 to 24, 26.7% from 25 to 44, 26.7% from 45 to 64, and 36.7% who were 65 years of age or older. The median age was 56 years. For every 100 females there were 100.0 males. For every 100 females age 18 and over, there were 100.0 males.

The median income for a household in the village was $40,000, and the median income for a family was $41,250. Males had a median income of $26,250 versus $22,500 for females. The per capita income for the village was $22,977. None of the population and none of the families were below the poverty line.