Talk:Circulant matrix

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You have new messages (last change).

Shouldn't

n \mathcal{F}_{n}(\mathbf{c} * \mathbf{x}) = n \mathcal{F}_{n}(c) \mathcal{F}_{n}(\mathbf{x}) = \mathcal{F}_{n}(\mathbf{b})

be


\mathcal{F}_{n}(\mathbf{c} * \mathbf{x}) = \mathcal{F}_{n}(c) \mathcal{F}_{n}(\mathbf{x}) = \mathcal{F}_{n}(\mathbf{b})

? - Connelly 00:57, 12 November 2005 (UTC)

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