Centerville, South Dakota

From Wikipedia, the free encyclopedia

Centerville is a city in Turner County, South Dakota, United States. The population was 910 at the 2000 census.

[edit] Geography

Centerville is located at 43°7′3″N, 96°57′38″W (43.117631, -96.960644)^GR1.

According to the United States Census Bureau, the city has a total area of 1.9 km² (0.7 mi²), all land.

Centerville has been assigned the ZIP code 57014 and the FIPS place code 11060.

[edit] Demographics

As of the census^GR2 of 2000, there were 910 people, 387 households, and 236 families residing in the city. The population density was 488.0/km² (1,265.9/mi²). There were 429 housing units at an average density of 230.1/km² (596.8/mi²). The racial makeup of the city was 99.34% White, 0.11% Native American, 0.11% Asian, and 0.44% from two or more races. Hispanic or Latino of any race were 0.66% of the population.

There were 387 households out of which 26.1% had children under the age of 18 living with them, 50.9% were married couples living together, 6.7% had a female householder with no husband present, and 38.8% were non-families. 35.4% of all households were made up of individuals and 22.5% had someone living alone who was 65 years of age or older. The average household size was 2.23 and the average family size was 2.90.

In the city the population was spread out with 23.6% under the age of 18, 6.3% from 18 to 24, 22.2% from 25 to 44, 20.2% from 45 to 64, and 27.7% who were 65 years of age or older. The median age was 44 years. For every 100 females there were 87.2 males. For every 100 females age 18 and over, there were 81.9 males.

The median income for a household in the city was $29,615, and the median income for a family was $39,643. Males had a median income of $27,171 versus $20,000 for females. The per capita income for the city was $17,089. About 4.2% of families and 8.2% of the population were below the poverty line, including 2.3% of those under age 18 and 19.1% of those age 65 or over.