Talk:Capacitance multiplier

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"the output voltage is about 0.65V less than the base voltage, which in turn is about 2 to 3V less than Vs." - Why is the base voltage about 2 to 3V less than Vs? Surely this will depend on the load impedance. If there's no load then the base voltage will gradually rise to Vs.

When loaded, the voltage across the capacitor which is also the base voltage will drop depending on the charging current through the resistor - this current causes a voltage to be developed across the resistor. The drop (and hence the base voltage) is not constant DC but a ripple superimposed on a DC. User:Rohitbd
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