Camp Douglas, Wisconsin

From Wikipedia, the free encyclopedia

Camp Douglas is a village in Juneau County, Wisconsin, United States. The population was 592 at the 2000 census.

[edit] Geography

Camp Douglas is located at 43°55′16″N, 90°16′12″W (43.921199, -90.269923)^GR1.

According to the United States Census Bureau, the village has a total area of 2.5 km² (0.9 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 592 people, 242 households, and 154 families residing in the village. The population density was 240.6/km² (621.9/mi²). There were 264 housing units at an average density of 107.3/km² (277.3/mi²). The racial makeup of the village was 97.64% White, 0.17% African American, 1.01% Native American, 0.34% Asian, 0.17% from other races, and 0.68% from two or more races. Hispanic or Latino of any race were 1.69% of the population.

There were 242 households out of which 35.1% had children under the age of 18 living with them, 49.2% were married couples living together, 11.2% had a female householder with no husband present, and 36.0% were non-families. 30.2% of all households were made up of individuals and 16.1% had someone living alone who was 65 years of age or older. The average household size was 2.45 and the average family size was 3.08.

In the village the population was spread out with 29.6% under the age of 18, 5.9% from 18 to 24, 30.4% from 25 to 44, 19.4% from 45 to 64, and 14.7% who were 65 years of age or older. The median age was 34 years. For every 100 females there were 100.0 males. For every 100 females age 18 and over, there were 94.9 males.

The median income for a household in the village was $39,583, and the median income for a family was $44,038. Males had a median income of $31,324 versus $21,607 for females. The per capita income for the village was $17,919. About 2.6% of families and 2.8% of the population were below the poverty line, including 1.3% of those under age 18 and 2.2% of those age 65 or over.