Calvin, North Dakota

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Calvin is a city in Cavalier County, North Dakota in the United States. The population was 26 at the 2000 census. Calvin was founded in 1905.

[edit] Geography

Location of Calvin, North Dakota

Calvin is located at 48°51′4″N, 98°56′15″W (48.851162, -98.937397)GR1.

According to the United States Census Bureau, the city has a total area of 0.6 km² (0.2 mi²), all land.

[edit] Demographics

As of the censusGR2 of 2000, there were 26 people, 11 households, and 6 families residing in the city. The population density was 45.6/km² (119.3/mi²). There were 19 housing units at an average density of 33.3/km² (87.2/mi²). The racial makeup of the city was 100.00% White.

There were 11 households out of which 27.3% had children under the age of 18 living with them, 54.5% were married couples living together, 9.1% had a female householder with no husband present, and 36.4% were non-families. 36.4% of all households were made up of individuals and 9.1% had someone living alone who was 65 years of age or older. The average household size was 2.36 and the average family size was 3.14.

In the city the population was spread out with 30.8% under the age of 18, 23.1% from 25 to 44, 30.8% from 45 to 64, and 15.4% who were 65 years of age or older. The median age was 44 years. For every 100 females there were 188.9 males. For every 100 females age 18 and over, there were 157.1 males.

The median income for a household in the city was $31,667, and the median income for a family was $81,250. Males had a median income of $21,250 versus $56,250 for females. The per capita income for the city was $27,878. None of the population and none of the families were below the poverty line.

[edit] External links

Flag of North Dakota State of North Dakota
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