Calvert, Texas

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Calvert is a city in Robertson County, Texas, United States. The population was 1,426 at the 2000 census.

1 Geography
2 Demographics
3 Education
4 External links

[edit] Geography

Calvert is located at 30°58′42″N, 96°40′22″W (30.978215, -96.672767)^GR1.

According to the United States Census Bureau, the city has a total area of 10.1 km² (3.9 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 1,426 people, 574 households, and 374 families residing in the city. The population density was 141.5/km² (366.6/mi²). There were 726 housing units at an average density of 72.1/km² (186.6/mi²). The racial makeup of the city was 36.89% White, 52.38% African American, 0.42% Native American, 0.07% Asian, 8.77% from other races, and 1.47% from two or more races. Hispanic or Latino of any race were 14.87% of the population.

There were 574 households out of which 27.4% had children under the age of 18 living with them, 34.7% were married couples living together, 25.4% had a female householder with no husband present, and 34.7% were non-families. 32.4% of all households were made up of individuals and 16.6% had someone living alone who was 65 years of age or older. The average household size was 2.44 and the average family size was 3.07.

In the city the population was spread out with 29.7% under the age of 18, 7.1% from 18 to 24, 21.9% from 25 to 44, 22.1% from 45 to 64, and 19.1% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 85.2 males. For every 100 females age 18 and over, there were 78.0 males.

The median income for a household in the city was $18,105, and the median income for a family was $23,214. Males had a median income of $24,722 versus $17,885 for females. The per capita income for the city was $13,165. About 30.3% of families and 36.9% of the population were below the poverty line, including 53.4% of those under age 18 and 32.6% of those age 65 or over.