Callaway, Nebraska

From Wikipedia, the free encyclopedia

Callaway is a village in Custer County, Nebraska, United States. The population was 637 at the 2000 census.

[edit] Geography

Callaway is located at 41°17′29″N, 99°55′23″W (41.291348, -99.923179)^GR1.

According to the United States Census Bureau, the village has a total area of 1.8 km² (0.7 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 637 people, 262 households, and 166 families residing in the village. The population density was 356.4/km² (916.8/mi²). There were 291 housing units at an average density of 162.8/km² (418.8/mi²). The racial makeup of the village was 97.49% White, 0.31% Native American, 0.31% Asian, 0.78% from other races, and 1.10% from two or more races. Hispanic or Latino of any race were 1.41% of the population.

There were 262 households out of which 25.2% had children under the age of 18 living with them, 57.6% were married couples living together, 5.7% had a female householder with no husband present, and 36.3% were non-families. 32.4% of all households were made up of individuals and 23.3% had someone living alone who was 65 years of age or older. The average household size was 2.27 and the average family size was 2.87.

In the village the population was spread out with 22.8% under the age of 18, 4.9% from 18 to 24, 17.4% from 25 to 44, 24.5% from 45 to 64, and 30.5% who were 65 years of age or older. The median age was 48 years. For every 100 females there were 76.9 males. For every 100 females age 18 and over, there were 80.2 males.

The median income for a household in the village was $27,656, and the median income for a family was $37,000. Males had a median income of $24,188 versus $16,591 for females. The per capita income for the village was $14,673. About 7.2% of families and 14.6% of the population were below the poverty line, including 24.0% of those under age 18 and 12.0% of those age 65 or over.