Byron, Wyoming

From Wikipedia, the free encyclopedia

Byron is a town in Big Horn County, Wyoming, United States. The population was 557 at the 2000 census.

[edit] Geography

Byron is located at 44°47′48″N, 108°30′21″W (44.796653, -108.505773)^GR1.

According to the United States Census Bureau, the town has a total area of 2.3 km² (0.9 mi²). 2.2 km² (0.8 mi²) of it is land and 0.1 km² (0.1 mi²) of it (5.62%) is water.

[edit] Demographics

As of the census^GR2 of 2000, there were 557 people, 195 households, and 148 families residing in the town. The population density was 256.0/km² (662.8/mi²). There were 217 housing units at an average density of 99.7/km² (258.2/mi²). The racial makeup of the town was 90.84% White, 0.36% Native American, 7.18% from other races, and 1.62% from two or more races. Hispanic or Latino of any race were 14.00% of the population.

There were 195 households out of which 37.4% had children under the age of 18 living with them, 57.4% were married couples living together, 14.9% had a female householder with no husband present, and 23.6% were non-families. 20.0% of all households were made up of individuals and 9.7% had someone living alone who was 65 years of age or older. The average household size was 2.86 and the average family size was 3.34.

In the town the population was spread out with 32.9% under the age of 18, 7.4% from 18 to 24, 21.2% from 25 to 44, 24.8% from 45 to 64, and 13.8% who were 65 years of age or older. The median age was 34 years. For every 100 females there were 106.3 males. For every 100 females age 18 and over, there were 93.8 males.

The median income for a household in the town was $34,375, and the median income for a family was $37,045. Males had a median income of $33,409 versus $16,667 for females. The per capita income for the town was $11,931. About 19.9% of families and 22.6% of the population were below the poverty line, including 34.6% of those under age 18 and 9.1% of those age 65 or over.