Burnside, Wisconsin
From Wikipedia, the free encyclopedia
Burnside is a town in Trempealeau County, Wisconsin, in the United States. As of the 2000 census, the population was 529.
[edit] Geography
According to the United States Census Bureau, the town has a total area of 90.8 km² (35.0 mi²). 90.6 km² (35.0 mi²) of it is land and 0.1 km² (0.1 mi²) of it (0.14%) is water.
[edit] Demographics
As of the census2 of 2000, there were 529 people, 197 households, and 144 families residing in the town. The population density was 5.8/km² (15.1/mi²). There were 202 housing units at an average density of 2.2/km² (5.8/mi²). The racial makeup of the town was 99.43% White, and 0.57% from two or more races. Hispanic or Latino of any race were 0.38% of the population.
There were 197 households out of which 32.0% had children under the age of 18 living with them, 59.4% were married couples living together, 7.1% had a female householder with no husband present, and 26.9% were non-families. 22.8% of all households were made up of individuals and 10.7% had someone living alone who was 65 years of age or older. The average household size was 2.69 and the average family size was 3.15.
In the town the population was spread out with 26.8% under the age of 18, 8.3% from 18 to 24, 28.9% from 25 to 44, 21.0% from 45 to 64, and 14.9% who were 65 years of age or older. The median age was 37 years. For every 100 females there were 115.0 males. For every 100 females age 18 and over, there were 122.4 males.
The median income for a household in the town was $41,111, and the median income for a family was $46,250. Males had a median income of $26,989 versus $21,167 for females. The per capita income for the town was $18,612. About 2.2% of families and 6.5% of the population were below the poverty line, including 6.3% of those under age 18 and 6.8% of those age 65 or over.
