Brownstown, Illinois

From Wikipedia, the free encyclopedia

Brownstown is a village in Fayette County, Illinois, United States. The population was 705 at the 2000 census.

[edit] Geography

Brownstown is located at 38°59′43″N, 88°57′12″W (38.995403, -88.953217)^GR1.

According to the United States Census Bureau, the village has a total area of 1.6 km² (0.6 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 705 people, 293 households, and 189 families residing in the village. The population density was 432.1/km² (1,123.0/mi²). There were 317 housing units at an average density of 194.3/km² (505.0/mi²). The racial makeup of the village was 98.01% White, 0.57% African American, 0.43% Native American, 0.14% Asian, 0.43% from other races, and 0.43% from two or more races. Hispanic or Latino of any race were 0.57% of the population.

There were 293 households out of which 31.1% had children under the age of 18 living with them, 50.2% were married couples living together, 11.3% had a female householder with no husband present, and 35.2% were non-families. 31.1% of all households were made up of individuals and 16.4% had someone living alone who was 65 years of age or older. The average household size was 2.39 and the average family size was 2.93.

In the village the population was spread out with 25.2% under the age of 18, 9.5% from 18 to 24, 27.0% from 25 to 44, 21.8% from 45 to 64, and 16.5% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 72.0 males. For every 100 females age 18 and over, there were 78.6 males.

The median income for a household in the village was $28,839, and the median income for a family was $33,750. Males had a median income of $28,438 versus $21,250 for females. The per capita income for the village was $15,239. About 9.9% of families and 14.8% of the population were below the poverty line, including 14.3% of those under age 18 and 13.1% of those age 65 or over.