Bristow, Nebraska

From Wikipedia, the free encyclopedia

Bristow is a village in Boyd County, Nebraska, United States. The population was 88 at the 2000 census.

[edit] Geography

Bristow is located at 42°50′23″N, 98°35′2″W (42.839601, -98.583940)^GR1.

According to the United States Census Bureau, the village has a total area of 0.4 km² (0.2 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 88 people, 40 households, and 26 families residing in the village. The population density was 199.9/km² (506.4/mi²). There were 53 housing units at an average density of 120.4/km² (305.0/mi²). The racial makeup of the village was 95.45% White, 3.41% Native American, and 1.14% from two or more races.

There were 40 households out of which 27.5% had children under the age of 18 living with them, 57.5% were married couples living together, 2.5% had a female householder with no husband present, and 35.0% were non-families. 35.0% of all households were made up of individuals and 17.5% had someone living alone who was 65 years of age or older. The average household size was 2.20 and the average family size was 2.81.

In the village the population was spread out with 19.3% under the age of 18, 8.0% from 18 to 24, 20.5% from 25 to 44, 26.1% from 45 to 64, and 26.1% who were 65 years of age or older. The median age was 46 years. For every 100 females there were 131.6 males. For every 100 females age 18 and over, there were 129.0 males.

The median income for a household in the village was $28,125, and the median income for a family was $33,438. Males had a median income of $18,125 versus $16,250 for females. The per capita income for the village was $11,737. There were 7.4% of families and 10.1% of the population living below the poverty line, including 20.0% of under eighteens and 12.5% of those over 64.