Belgium, Wisconsin

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Looking east at Belgium's business district

Belgium is a village located in the Town of Belgium in Ozaukee County, Wisconsin. The population was 1,678 at the 2000 census.

[edit] Geography

Belgium is located at 43°30′2″N, 87°50′48″W (43.500735, -87.846897)^GR1. According to the United States Census Bureau, the village has a total area of 3.7 km² (1.4 mi²). None of the area is covered with water.

[edit] Demographics

As of the census^GR2 of 2000, there were 1,678 people, 582 households, and 444 families residing in the village. The population density was 449.9/km² (1,163.0/mi²). There were 592 housing units at an average density of 158.7/km² (410.3/mi²). The racial makeup of the village was 96.31% White, 0.48% Black or African American, 0.42% Native American, 0.18% Asian, 1.49% from other races, and 1.13% from two or more races. 4.11% of the population were Hispanic or Latino of any race.

There were 582 households out of which 44.5% had children under the age of 18 living with them, 67.9% were married couples living together, 5.8% had a female householder with no husband present, and 23.7% were non-families. 19.6% of all households were made up of individuals and 7.4% had someone living alone who was 65 years of age or older. The average household size was 2.85 and the average family size was 3.31.

In the village the population was spread out with 31.8% under the age of 18, 6.8% from 18 to 24, 36.1% from 25 to 44, 16.5% from 45 to 64, and 8.8% who were 65 years of age or older. The median age was 32 years. For every 100 females there were 101.2 males. For every 100 females age 18 and over, there were 99.5 males.

The median income for a household in the village was $53,523, and the median income for a family was $59,375. Males had a median income of $40,152 versus $25,609 for females. The per capita income for the village was $20,659. About 1.8% of families and 2.4% of the population were below the poverty line, including 2.8% of those under age 18 and 6.0% of those age 65 or over.