Auburn, Wyoming

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Auburn is a census-designated place (CDP) in Lincoln County, Wyoming, in the United States. As of the 2000 census, the CDP population was 276.

[edit] Geography

Auburn is located at 42°47′40″N, 111°0′18″W (42.794401, -111.004929)^GR1.

According to the United States Census Bureau, the CDP has a total area of 5.5 km² (2.1 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 276 people, 85 households, and 74 families residing in the CDP. The population density was 49.8/km² (128.8/mi²). There were 94 housing units at an average density of 17.0/km² (43.9/mi²). The racial makeup of the CDP was 98.19% White, 0.36% from other races, and 1.45% from two or more races. Hispanic or Latino of any race were 0.72% of the population.

There were 85 households out of which 37.6% had children under the age of 18 living with them, 77.6% were married couples living together, 8.2% had a female householder with no husband present, and 11.8% were non-families. 9.4% of all households were made up of individuals and 5.9% had someone living alone who was 65 years of age or older. The average household size was 3.25 and the average family size was 3.45.

In the CDP the population was spread out with 32.6% under the age of 18, 11.2% from 18 to 24, 23.2% from 25 to 44, 23.9% from 45 to 64, and 9.1% who were 65 years of age or older. The median age was 30 years. For every 100 females there were 107.5 males. For every 100 females age 18 and over, there were 102.2 males.

The median income for a household in the CDP was $33,125, and the median income for a family was $35,083. Males had a median income of $29,583 versus $15,208 for females. The per capita income for the CDP was $9,932. About 17.3% of families and 22.3% of the population were below the poverty line, including 34.8% of those under the age of eighteen and none of those sixty five or over.