Armstrong, Iowa

From Wikipedia, the free encyclopedia

Armstrong is a city in Emmet County, Iowa, United States. The population was 979 at the 2000 census.

[edit] Geography

Armstrong is located at 43°23′45″N, 94°28′51″W (43.395722, -94.480750)^GR1.

According to the United States Census Bureau, the city has a total area of 2.1 km² (0.8 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 979 people, 422 households, and 268 families residing in the city. The population density was 461.0/km² (1,192.7/mi²). There were 456 housing units at an average density of 214.7/km² (555.5/mi²). The racial makeup of the city was 98.88% White, 0.20% African American, 0.41% Native American, 0.10% Asian, 0.10% from other races, and 0.31% from two or more races. Hispanic or Latino of any race were 0.31% of the population.

There were 422 households out of which 25.4% had children under the age of 18 living with them, 55.9% were married couples living together, 5.0% had a female householder with no husband present, and 36.3% were non-families. 33.4% of all households were made up of individuals and 19.0% had someone living alone who was 65 years of age or older. The average household size was 2.21 and the average family size was 2.83.

In the city the population was spread out with 20.6% under the age of 18, 6.8% from 18 to 24, 21.1% from 25 to 44, 26.4% from 45 to 64, and 25.0% who were 65 years of age or older. The median age was 46 years. For every 100 females there were 90.5 males. For every 100 females age 18 and over, there were 88.6 males.

The median income for a household in the city was $35,446, and the median income for a family was $45,563. Males had a median income of $31,210 versus $19,732 for females. The per capita income for the city was $16,221. About 3.0% of families and 8.0% of the population were below the poverty line, including 7.1% of those under age 18 and 16.5% of those age 65 or over.