Alder, Montana

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Alder is a census-designated place in Madison County, Montana, United States. The population was 116 at the 2000 census.

1 Geography
2 Demographics
3 External links
4 External links

[edit] Geography

Alder is located at 45°19′28″N, 112°6′29″W (45.324531, -112.108035)^GR1.

According to the United States Census Bureau, the CDP has a total area of 5.2 km² (2.0 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 116 people, 48 households, and 25 families residing in the CDP. The population density was 22.3/km² (57.6/mi²). There were 69 housing units at an average density of 13.3/km² (34.3/mi²). The racial makeup of the CDP was 100.00% White.

There were 48 households out of which 27.1% had children under the age of 18 living with them, 45.8% were married couples living together, 4.2% had a female householder with no husband present, and 47.9% were non-families. 33.3% of all households were made up of individuals and 16.7% had someone living alone who was 65 years of age or older. The average household size was 2.42 and the average family size was 3.44.

In the CDP the population was spread out with 26.7% under the age of 18, 6.0% from 18 to 24, 27.6% from 25 to 44, 27.6% from 45 to 64, and 12.1% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 110.9 males. For every 100 females age 18 and over, there were 107.3 males.

The median income for a household in the CDP was $26,458, and the median income for a family was $33,750. Males had a median income of $22,500 versus $30,000 for females. The per capita income for the CDP was $16,300. There were no families and 1.8% of the population living below the poverty line, including no under eighteens and none of those over 64.