Akron, Alabama

From Wikipedia, the free encyclopedia

Akron is a town in Hale County, Alabama, United States. At the 2000 census the population was 521. According to the 2005 U.S. Census estimates, the city had a population of 514. ^[1].

1 Geography
2 Demographics
3 References
4 External links

[edit] Geography

Akron is located at 32°52′35″N, 87°44′28″W (32.876425, -87.740978)^GR1.

According to the U.S. Census Bureau, the town has a total area of 1.4 km² (0.6 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 521 people, 207 households, and 142 families residing in the town. The population density was 365.7/km² (939.2/mi²). There were 239 housing units at an average density of 167.8/km² (430.8/mi²). The racial makeup of the town was 17.85% White, 81.00% Black or African American, and 1.15% from two or more races. 1.54% of the population were Hispanic or Latino of any race.

There were 207 households out of which 36.7% had children under the age of 18 living with them, 34.8% were married couples living together, 30.9% had a female householder with no husband present, and 31.4% were non-families. 28.5% of all households were made up of individuals and 14.5% had someone living alone who was 65 years of age or older. The average household size was 2.52 and the average family size was 3.15.

In the town the population was spread out with 29.4% under the age of 18, 9.8% from 18 to 24, 25.3% from 25 to 44, 20.9% from 45 to 64, and 14.6% who were 65 years of age or older. The median age was 32 years. For every 100 females there were 81.5 males. For every 100 females age 18 and over, there were 68.8 males.

The median income for a household in the town was $19,875, and the median income for a family was $21,250. Males had a median income of $22,396 versus $18,500 for females. The per capita income for the town was $10,929. About 37.1% of families and 40.7% of the population were below the poverty line, including 60.2% of those under age 18 and 32.7% of those age 65 or over.